5x^4-19x^2+12=0

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Solution for 5x^4-19x^2+12=0 equation:


Simplifying
5x4 + -19x2 + 12 = 0

Reorder the terms:
12 + -19x2 + 5x4 = 0

Solving
12 + -19x2 + 5x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -5x2)(3 + -1x2) = 0

Subproblem 1

Set the factor '(4 + -5x2)' equal to zero and attempt to solve: Simplifying 4 + -5x2 = 0 Solving 4 + -5x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5x2 = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5x2 = 0 + -4 -5x2 = 0 + -4 Combine like terms: 0 + -4 = -4 -5x2 = -4 Divide each side by '-5'. x2 = 0.8 Simplifying x2 = 0.8 Take the square root of each side: x = {-0.894427191, 0.894427191}

Subproblem 2

Set the factor '(3 + -1x2)' equal to zero and attempt to solve: Simplifying 3 + -1x2 = 0 Solving 3 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1x2 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1x2 = 0 + -3 -1x2 = 0 + -3 Combine like terms: 0 + -3 = -3 -1x2 = -3 Divide each side by '-1'. x2 = 3 Simplifying x2 = 3 Take the square root of each side: x = {-1.732050808, 1.732050808}

Solution

x = {-0.894427191, 0.894427191, -1.732050808, 1.732050808}

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